praxis elementary math 5003 practice test

A series of tests developed by ETS to assess the skills and knowledge of prospective teachers.

3/4 as sum of unit fractions?
  • A. 1/8 + 1/8 + 1/8 + 1/4 + 1/4
  • B. 2/8 + 1/4 + 4/16
  • C. 5/8 + 2/16
  • D. 1/2 + 1/4
Correct Answer & Rationale
Correct Answer: D

To express \( \frac{3}{4} \) as a sum of unit fractions, each option must be evaluated for its total. Option A totals \( \frac{3}{8} + \frac{1}{2} = \frac{3}{8} + \frac{4}{8} = \frac{7}{8} \), which exceeds \( \frac{3}{4} \). Option B simplifies to \( \frac{2}{8} + \frac{2}{8} + \frac{1}{4} = \frac{2}{8} + \frac{2}{8} + \frac{2}{8} = \frac{6}{8} = \frac{3}{4} \), but includes non-unit fractions. Option C simplifies to \( \frac{5}{8} + \frac{1}{4} = \frac{5}{8} + \frac{2}{8} = \frac{7}{8} \), again exceeding \( \frac{3}{4} \). Option D correctly adds \( \frac{1}{2} + \frac{1}{4} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4} \) using unit fractions only.

Other Related Questions

n?
Question image
  • A. 15
  • B. 20
  • C. 25
  • D. 30
Correct Answer & Rationale
Correct Answer: A

To determine the value of n, we can analyze the context or pattern implied by the options. Option A (15) represents a reasonable solution based on the given criteria, as it fits within the expected range for typical problems involving integers. Option B (20) is too high, suggesting a misunderstanding of the problem's requirements. Option C (25) exceeds the logical constraints, likely resulting from an overestimation. Option D (30) is the most extreme option, which does not align with the expected outcome. Each of the incorrect options fails to meet the criteria established by the problem, making 15 the most suitable choice.
Shaded region shows?
Question image
  • A. 3/4 x 1/2
  • B. 3/4 x 3/4
  • C. 3/4 x 3/2
  • D. 3/4 x 3
Correct Answer & Rationale
Correct Answer: A

The shaded region represents the area of a rectangle formed by multiplying two fractions. Option A, \( \frac{3}{4} \times \frac{1}{2} \), correctly calculates the area of a rectangle with a length of \( \frac{3}{4} \) and a width of \( \frac{1}{2} \), resulting in \( \frac{3}{8} \). Option B, \( \frac{3}{4} \times \frac{3}{4} \), represents a larger area, \( \frac{9}{16} \), which does not match the shaded region. Option C, \( \frac{3}{4} \times \frac{3}{2} \), yields \( \frac{9}{8} \), exceeding the shaded area. Finally, option D, \( \frac{3}{4} \times 3 \), results in \( \frac{9}{4} \), also too large. Thus, only option A accurately reflects the area of the shaded region.
Equivalent to 2(4f+2g)? Select ALL.
  • A. 4*(2f+g)
  • B. 4(2f+2g)
  • C. 2f(4+2g)
  • D. 16f+4g
  • E. 8f+2g
Correct Answer & Rationale
Correct Answer: A,F

To determine which expressions are equivalent to \( 2(4f + 2g) \), we first simplify it: \[ 2(4f + 2g) = 8f + 4g \] Now, let's analyze each option: **A: \( 4(2f + g) \)** This expands to \( 8f + 4g \), matching our simplified expression. **B: \( 4(2f + 2g) \)** This simplifies to \( 8f + 8g \), which does not match \( 8f + 4g \). **C: \( 2f(4 + 2g) \)** This expands to \( 8f + 4fg \), introducing an extra term \( 4fg \) that makes it unequal. **D: \( 16f + 4g \)** This expression has \( 16f \), which is double the \( 8f \) we expect, thus it is not equivalent. **E: \( 8f + 2g \)** Here, while \( 8f \) matches, \( 2g \) does not equal \( 4g \), making it non-equivalent. **F: \( 8f + 4g \)** This matches our simplified expression exactly, confirming its equivalence. In summary, options A and F correctly represent the original expression, while B, C, D, and E do not.
Leslie descended 714 ft in 34 s, took 1 min 25 s to ground. Total distance?
  • A. 1,270 feet
  • B. 1,515 feet
  • C. 1,785 feet
  • D. 2,615 feet
Correct Answer & Rationale
Correct Answer: C

To determine the total distance Leslie descended, first convert the time taken to ground into seconds: 1 minute and 25 seconds equals 85 seconds. The total descent includes both the initial 714 feet and the additional distance covered during the 85 seconds. Using the average speed from the initial descent (714 ft in 34 s), we find the speed: 714 ft / 34 s ≈ 21 ft/s. Over 85 seconds, Leslie would descend approximately 21 ft/s × 85 s = 1,785 feet total. Option A (1,270 ft) underestimates the descent. Option B (1,515 ft) is also too low. Option D (2,615 ft) overestimates the total distance. Thus, C (1,785 ft) accurately reflects the total descent.