tsia2 math practice test

A placement test used in Texas to assess a student's readiness for college-level coursework in math, reading, and writing.

Choose the best answer. If necessary, use the paper you were given.
If (2w + 7)(3w - 1) = 0 which of the following is a possible value of w?
  • A. -3
  • B. -0.28571
  • C. 01-Mar
  • D. 07-Feb
Correct Answer & Rationale
Correct Answer: D

To solve the equation (2w + 7)(3w - 1) = 0, we set each factor to zero. 1. For 2w + 7 = 0, solving gives w = -3. This corresponds to option A, which is a valid solution. 2. For 3w - 1 = 0, solving gives w = 1/3, approximately 0.333. Option B, -0.28571, does not match this value. 3. Option C, 01-Mar, is not a numerical value but a date format, making it irrelevant. 4. Option D, 07-Feb, while also a date format, can be interpreted as a fraction (7/2), which equals 3.5, not a solution to the equation. Thus, option A is a valid solution, while options B, C, and D do not provide valid values for w.

Other Related Questions

During a sale, the regular price of a pair of running shoes is reduced by 20 percent. $64.00, what is the regular price of the running shoes?
  • A. $48.00
  • B. $51.20
  • C. $76.80
  • D. $80.00
Correct Answer & Rationale
Correct Answer: D

To find the regular price of the running shoes, we need to determine what amount, when reduced by 20%, equals $64.00. This can be calculated using the formula: Sale Price = Regular Price × (1 - Discount Rate). Here, the discount rate is 20%, or 0.20. Therefore, the equation becomes $64.00 = Regular Price × 0.80. Solving for Regular Price gives us $64.00 / 0.80 = $80.00. Option A ($48.00) is incorrect because it suggests a much larger discount than 20%. Option B ($51.20) miscalculates the reduction, indicating a 36% discount. Option C ($76.80) inaccurately reflects a smaller discount, resulting in an incorrect sale price. Thus, only option D correctly represents the regular price before the 20% reduction.
Which of the following is a factor of u²+uv-2v²?
  • A. (u-v)
  • B. (2u-v)
  • C. (u-2v)
  • D. (u+v)
Correct Answer & Rationale
Correct Answer: C

To determine the factors of \( u^2 + uv - 2v^2 \), we can factor the expression. Option C, \( (u - 2v) \), is a valid factor. When we perform polynomial long division or synthetic division using \( (u - 2v) \), we find that it divides evenly, confirming it as a factor. Option A, \( (u - v) \), does not satisfy the factorization, as substituting \( v \) does not yield a zero remainder. Option B, \( (2u - v) \), also fails to factor the expression correctly, leading to a non-zero remainder upon division. Option D, \( (u + v) \), similarly does not yield a zero remainder, confirming it is not a factor. Thus, only \( (u - 2v) \) is a valid factor of the expression.
A playground at a mall is in the shape of a rectangle, and there is a 144 foot long fence around it. If the rectangle is 6 feet longer than it is wide, what is the width, in feet, of the rectangle?
  • A. 33
  • B. 39
  • C. 69
  • D. 75
Correct Answer & Rationale
Correct Answer: A

To find the width of the rectangle, let the width be represented as \( w \). The length, being 6 feet longer, can be expressed as \( w + 6 \). The perimeter of a rectangle is given by the formula \( P = 2(l + w) \). Here, the perimeter is 144 feet, leading to the equation \( 2(w + (w + 6)) = 144 \). Simplifying this gives \( 2(2w + 6) = 144 \), which reduces to \( 4w + 12 = 144 \), and further simplifies to \( 4w = 132 \), resulting in \( w = 33 \). Option B (39) is incorrect as it gives a perimeter of 156 feet. Option C (69) would lead to an impossible perimeter of 150 feet. Option D (75) results in a perimeter of 162 feet, which exceeds the given value. Thus, only option A satisfies all conditions, confirming the width as 33 feet.
What is the range of her scores?
  • A. 100
  • B. 120
  • C. 440
  • D. 2,250
Correct Answer & Rationale
Correct Answer: B

To determine the range of her scores, we subtract the lowest score from the highest score. If the highest score is 220 and the lowest is 100, the calculation is 220 - 100 = 120, which represents the range. Option A (100) misrepresents the range as it does not account for the difference between the highest and lowest scores. Option C (440) and Option D (2,250) are excessively high and do not reflect the actual spread of scores based on the provided data. Thus, 120 accurately represents the range of her scores.