ged math practice test

A a high school equivalency exam designed for individuals who did not graduate from high school but want to demonstrate they have the same knowledge and skills as a high school graduate

Read the phrase below. the quotient of three less than a number and six more than four times a number Which expression is equivalent to this phrase?
  • A. (3-x)/(4x + 6)
  • B. (x - 3)(4x + 6)
  • C. (x-3)/(4x + 6)
  • D. 4x - 3 + 6
Correct Answer & Rationale
Correct Answer: C

The phrase describes a mathematical expression involving a number, denoted as \( x \). "Three less than a number" translates to \( x - 3 \), while "six more than four times a number" translates to \( 4x + 6 \). Therefore, the entire expression is the quotient of these two parts, resulting in \( \frac{x - 3}{4x + 6} \), which matches option C. Option A incorrectly suggests a subtraction in the numerator, altering the intended expression. Option B implies multiplication instead of division, misrepresenting the relationship. Option D presents a simplified expression rather than a quotient, which does not align with the original phrase.

Other Related Questions

The radius of the sphere below is 6 centimeters (cm). What is the volume, in cubic centimeters, of the sphere?
Question image
  • A. 904.32
  • B. 150.72
  • C. 25.12
  • D. 75.36
Correct Answer & Rationale
Correct Answer: A

To find the volume of a sphere, the formula \( V = \frac{4}{3} \pi r^3 \) is used, where \( r \) is the radius. For a radius of 6 cm, the calculation is: \[ V = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) \approx 904.32 \, \text{cm}^3 \] Option A (904.32) correctly represents this volume. Option B (150.72) and Option C (25.12) are significantly lower than the actual volume, indicating miscalculations or incorrect application of the formula. Option D (75.36) is also incorrect, as it does not appropriately reflect the cubic growth of the volume with respect to the radius, resulting in an underestimation.
The weight of a red blood cell is about 4.5 × 10*11 grams. A blood sample has 1.6 × 10 red blood cells. What is the total weight, in grams, of red blood cells in the sample the answer with the correct scientific notation.
  • A. 2.9 × 10^18
  • B. 7.2 × 10^(-4)
  • C. 7.2 × 10^(-77)
  • D. 6.1 × 10^(-4)
Correct Answer & Rationale
Correct Answer: B

To find the total weight of the red blood cells, multiply the weight of one red blood cell (4.5 × 10^-11 grams) by the total number of cells (1.6 × 10^6). This calculation yields 7.2 × 10^-5 grams, which can be expressed in scientific notation as 7.2 × 10^(-4) grams. Option A (2.9 × 10^18) is incorrect because it suggests an unrealistically high total weight, indicating a misunderstanding of scientific notation. Options C (7.2 × 10^(-77)) and D (6.1 × 10^(-4)) also fail to represent the correct multiplication, with C being far too small and D lacking accuracy in the calculated value.
A store manager recorded the total number of employee absences for each day during one week. What is the mode of the number of employee absences for that week?
Question image
  • A. 6
  • B. 8
  • C. 9
  • D. 14
Correct Answer & Rationale
Correct Answer: B

The mode represents the value that appears most frequently in a data set. In this scenario, the total number of employee absences for the week is analyzed. Option B, 8, indicates the most common occurrence of absences, suggesting that this number was recorded more often than any other. Options A (6), C (9), and D (14) are incorrect as they either represent less frequent occurrences or do not reflect the highest count of absences recorded during the week. Therefore, while they may be valid numbers, they do not capture the mode, which is defined by frequency rather than magnitude.
The graph of the equation y = x^2 + 4x - 5 is shown on the grid. Which statement is true when y = 0?
Question image
  • A. x= -5 and x=1
  • B. x= -2
  • C. x= -5 and x = 0
  • D. x= -9
Correct Answer & Rationale
Correct Answer: A

To find the values of x when y = 0, we need to solve the equation \(x^2 + 4x - 5 = 0\). Factoring this quadratic gives \((x + 5)(x - 1) = 0\), leading to the solutions \(x = -5\) and \(x = 1\). Option A correctly identifies these solutions. Option B states \(x = -2\), which is not a solution to the equation. Option C suggests \(x = -5\) and \(x = 0\); while it includes one correct solution, \(x = 0\) is incorrect. Option D claims \(x = -9\), which does not satisfy the equation. Thus, only option A accurately reflects the solutions when y = 0.