praxis elementary math 5003 practice test

A series of tests developed by ETS to assess the skills and knowledge of prospective teachers.

Compare 3 in 123,456 to others.
436,521 315,624 126,354 642,135
  • A. 100x_____
  • B. 10x_____
  • C. 0.1x_____
  • D. 0.01x_____
Correct Answer & Rationale
Correct Answer: B,A,C,D

To determine the appropriate multiplier for each number, we analyze their values: - **B: 10x_____** is valid as multiplying by 10 shifts the decimal point one place to the right, increasing the value significantly, making it suitable for larger numbers like 436,521 and 315,624. - **A: 100x_____** is also applicable, as multiplying by 100 shifts the decimal two places, further increasing the value. However, it is not the most fitting choice for the context of smaller increments. - **C: 0.1x_____** indicates a decrease in value, which applies to smaller numbers but is less relevant for the context of significant values like 126,354. - **D: 0.01x_____** further diminishes the number, making it the least appropriate option for the given values, as it reduces the numbers excessively. In conclusion, B is the best fit for maintaining relevance to the larger values, while A, C, and D serve progressively less appropriate roles.

Other Related Questions

178-degree angle?
  • A. Acute
  • B. Obtuse
  • C. Right
  • D. Straight
Correct Answer & Rationale
Correct Answer: B

An angle measuring 178 degrees is classified as obtuse, as it is greater than 90 degrees but less than 180 degrees. Option A, acute, refers to angles less than 90 degrees, which does not apply here. Option C, right, denotes a 90-degree angle, clearly not fitting for 178 degrees. Option D, straight, describes a 180-degree angle, which is also not applicable since 178 degrees is slightly less than that. Thus, the only suitable classification for a 178-degree angle is obtuse.
P=2(L+W), P=48, W=L-4. Width?
  • A. 10
  • B. 12
  • C. 20
  • D. 24
Correct Answer & Rationale
Correct Answer: A

To find the width (W), start with the given perimeter formula \( P = 2(L + W) \). Substituting \( P = 48 \) gives \( 48 = 2(L + W) \), which simplifies to \( L + W = 24 \). Given \( W = L - 4 \), substitute this into the equation: \( L + (L - 4) = 24 \). This simplifies to \( 2L - 4 = 24 \), leading to \( 2L = 28 \) and \( L = 14 \). Thus, \( W = 14 - 4 = 10 \). Option B (12) does not satisfy the perimeter equation. Option C (20) and Option D (24) also do not fit the derived equations, confirming that W must be 10.
Liz spent 1/2, 1/3, 1/4, $15 left. Birthday money?
  • A. $360
  • B. $180
  • C. $120
  • D. $60
Correct Answer & Rationale
Correct Answer: D

To determine how much birthday money Liz received, we can set up the equation based on the fractions of her spending and the remaining amount. Let \( x \) represent the total birthday money. She spent \( \frac{1}{2}x + \frac{1}{3}x + \frac{1}{4}x + 15 = x \). Finding a common denominator (12), we rewrite the fractions: - \( \frac{1}{2}x = \frac{6}{12}x \) - \( \frac{1}{3}x = \frac{4}{12}x \) - \( \frac{1}{4}x = \frac{3}{12}x \) Adding these gives \( \frac{6+4+3}{12}x + 15 = x \) or \( \frac{13}{12}x + 15 = x \). Rearranging yields \( 15 = x - \frac{13}{12}x \), simplifying to \( 15 = \frac{1}{12}x \). Therefore, \( x = 180 \). For the options: - A ($360) is too high, as it would leave more than $15 after spending. - B ($180) results in no remaining amount after spending. - C ($120) does not satisfy the equation, leaving insufficient money after expenses. - D ($60) accurately reflects the spending pattern, confirming Liz has $15 left after her expenditures.
d=rt, triple d, same t, new rate?
  • A. 3dt
  • B. (3d)/t
  • C. t/(3d)
  • D. d/(3t)
Correct Answer & Rationale
Correct Answer: B

In the equation d = rt, if distance (d) is tripled while time (t) remains constant, the new distance becomes 3d. To find the new rate (r'), we can rearrange the formula to r' = d/t. Substituting the new distance gives r' = (3d)/t, which is option B. Option A (3dt) incorrectly suggests multiplying distance by time, which does not represent rate. Option C (t/(3d)) misplaces the variables, implying time is divided by distance, which does not align with the rate formula. Option D (d/(3t)) incorrectly divides distance by three times the time, again misrepresenting the relationship between distance, rate, and time.