praxis elementary math 5003 practice test

A series of tests developed by ETS to assess the skills and knowledge of prospective teachers.

Graph: pumpkin weights.
Answerable?
Question image
  • A. 4.5 pounds?
  • B. At least 15?
  • C. Less than 8?
  • D. 6-12 pounds?
Correct Answer & Rationale
Correct Answer: B

Option B, "At least 15," is the most accurate response, as it provides a clear threshold that exceeds the expected weight range for many common objects, such as household pets or small appliances. Option A, "4.5 pounds," is too low for many items, making it an unreliable estimate. Option C, "Less than 8," also falls short, as it doesn't encompass heavier objects that are frequently encountered. Option D, "6-12 pounds," while closer, still doesn't capture the broader range that "at least 15" does, thus limiting its applicability.

Other Related Questions

Order 0.68, 1/12, 1(1/5), 3/5 least to greatest?
  • A. 1(1/5), 0.68, 3/5, 1/12
  • B. 1/12, 3/5, 0.68, 1(1/5)
  • C. 1/12, 0.68, 3/5, 1(1/5)
  • D. 0.68, 1/12, 3/5, 1(1/5)
Correct Answer & Rationale
Correct Answer: B

To compare the values, first convert them to a common format. - 1(1/5) equals 1.2. - 0.68 remains as is. - 3/5 converts to 0.6. - 1/12 is approximately 0.0833. Ordering these from least to greatest gives: 1/12 (0.0833), 3/5 (0.6), 0.68, and 1(1/5) (1.2). Option A incorrectly places 1(1/5) first, while C misplaces 3/5 and 0.68. Option D also misorders the values by placing 0.68 before 1/12. Thus, B accurately reflects the correct sequence of values.
Graph for data over time?
  • A. Bar
  • B. Line
  • C. Stem-and-leaf
  • D. Box-and-whisker
Correct Answer & Rationale
Correct Answer: B

A line graph is ideal for displaying data over time as it effectively shows trends and changes by connecting data points with a continuous line, making it easy to visualize patterns. Option A, a bar graph, is better suited for comparing discrete categories rather than illustrating changes over time. Option C, a stem-and-leaf plot, is primarily used for displaying the distribution of numerical data and is not designed for time-series analysis. Option D, a box-and-whisker plot, summarizes data distribution and highlights outliers but does not convey trends over time effectively.
Prism: 5.0cm, 7.3cm, 9.2cm. Surface area?
  • A. 149.66
  • B. 167.9
  • C. 299.32
  • D. 335.18
Correct Answer & Rationale
Correct Answer: C

To find the surface area of a rectangular prism, the formula is SA = 2(lw + lh + wh), where l, w, and h are the length, width, and height, respectively. Substituting the given dimensions (5.0 cm, 7.3 cm, and 9.2 cm) into the formula yields a surface area of 299.32 cm². Option A (149.66) likely results from miscalculating or omitting a dimension. Option B (167.9) may arise from incorrect multiplication or addition. Option D (335.18) could be a result of doubling the correct surface area without proper calculation. Thus, only option C accurately represents the surface area of the prism.
Favorite food via survey numbers. Best measure?
  • A. Mean
  • B. Median
  • C. Mode
  • D. Mean+median
Correct Answer & Rationale
Correct Answer: C

When analyzing survey data on favorite foods, the mode is the best measure since it identifies the most frequently chosen option, reflecting the popular preference among respondents. The mean can be skewed by outliers, making it less reliable in this context. The median, while useful for understanding the middle value, does not capture the most popular choice effectively. Combining mean and median (option D) does not address the core goal of identifying the favorite food, which is best represented by the mode. Thus, the mode provides a clear insight into the most favored food item.