Budget n dollars, x 50-cent, y 1-dollar ribbons.
n?
- A. 15
- B. 20
- C. 25
- D. 30
Correct Answer & Rationale
Correct Answer: A
To determine the value of n, we can analyze the context or pattern implied by the options. Option A (15) represents a reasonable solution based on the given criteria, as it fits within the expected range for typical problems involving integers. Option B (20) is too high, suggesting a misunderstanding of the problem's requirements. Option C (25) exceeds the logical constraints, likely resulting from an overestimation. Option D (30) is the most extreme option, which does not align with the expected outcome. Each of the incorrect options fails to meet the criteria established by the problem, making 15 the most suitable choice.
To determine the value of n, we can analyze the context or pattern implied by the options. Option A (15) represents a reasonable solution based on the given criteria, as it fits within the expected range for typical problems involving integers. Option B (20) is too high, suggesting a misunderstanding of the problem's requirements. Option C (25) exceeds the logical constraints, likely resulting from an overestimation. Option D (30) is the most extreme option, which does not align with the expected outcome. Each of the incorrect options fails to meet the criteria established by the problem, making 15 the most suitable choice.
Other Related Questions
Liz spent 1/2, 1/3, 1/4, $15 left. Birthday money?
- A. $360
- B. $180
- C. $120
- D. $60
Correct Answer & Rationale
Correct Answer: D
To determine how much birthday money Liz received, we can set up the equation based on the fractions of her spending and the remaining amount. Let \( x \) represent the total birthday money. She spent \( \frac{1}{2}x + \frac{1}{3}x + \frac{1}{4}x + 15 = x \). Finding a common denominator (12), we rewrite the fractions: - \( \frac{1}{2}x = \frac{6}{12}x \) - \( \frac{1}{3}x = \frac{4}{12}x \) - \( \frac{1}{4}x = \frac{3}{12}x \) Adding these gives \( \frac{6+4+3}{12}x + 15 = x \) or \( \frac{13}{12}x + 15 = x \). Rearranging yields \( 15 = x - \frac{13}{12}x \), simplifying to \( 15 = \frac{1}{12}x \). Therefore, \( x = 180 \). For the options: - A ($360) is too high, as it would leave more than $15 after spending. - B ($180) results in no remaining amount after spending. - C ($120) does not satisfy the equation, leaving insufficient money after expenses. - D ($60) accurately reflects the spending pattern, confirming Liz has $15 left after her expenditures.
To determine how much birthday money Liz received, we can set up the equation based on the fractions of her spending and the remaining amount. Let \( x \) represent the total birthday money. She spent \( \frac{1}{2}x + \frac{1}{3}x + \frac{1}{4}x + 15 = x \). Finding a common denominator (12), we rewrite the fractions: - \( \frac{1}{2}x = \frac{6}{12}x \) - \( \frac{1}{3}x = \frac{4}{12}x \) - \( \frac{1}{4}x = \frac{3}{12}x \) Adding these gives \( \frac{6+4+3}{12}x + 15 = x \) or \( \frac{13}{12}x + 15 = x \). Rearranging yields \( 15 = x - \frac{13}{12}x \), simplifying to \( 15 = \frac{1}{12}x \). Therefore, \( x = 180 \). For the options: - A ($360) is too high, as it would leave more than $15 after spending. - B ($180) results in no remaining amount after spending. - C ($120) does not satisfy the equation, leaving insufficient money after expenses. - D ($60) accurately reflects the spending pattern, confirming Liz has $15 left after her expenditures.
Cover floor? Select ALL.
- A. 15s4r
- B. 8s10r
- C. 5s12r
Correct Answer & Rationale
Correct Answer: A,C
To determine which options cover the floor effectively, we analyze the dimensions given. Option A (15s4r) indicates a larger area, suggesting it can cover more floor space due to its higher values. This makes it suitable for extensive coverage. Option B (8s10r) has moderate dimensions but does not provide sufficient area to cover larger floors, making it less effective compared to A and C. Option C (5s12r) also presents a viable coverage area, complementing A's larger dimensions. Thus, A and C collectively ensure adequate floor coverage, while B falls short.
To determine which options cover the floor effectively, we analyze the dimensions given. Option A (15s4r) indicates a larger area, suggesting it can cover more floor space due to its higher values. This makes it suitable for extensive coverage. Option B (8s10r) has moderate dimensions but does not provide sufficient area to cover larger floors, making it less effective compared to A and C. Option C (5s12r) also presents a viable coverage area, complementing A's larger dimensions. Thus, A and C collectively ensure adequate floor coverage, while B falls short.
Quickly multiply 24x16?
- A. 20x20-4x4
- B. 20x20
- C. 20x10+4x6
- D. 25x10+4x15
Correct Answer & Rationale
Correct Answer: A
Option A, 20x20 - 4x4, effectively utilizes the difference of squares method. It simplifies the multiplication by recognizing that 24 can be expressed as 20 + 4 and 16 as 20 - 4, leading to a calculation of (20+4)(20-4). Option B, 20x20, underestimates the value of 24 and 16, yielding only 400 instead of the correct 384. Option C, 20x10 + 4x6, inaccurately breaks down the multiplication, leading to 200 + 24, which totals 224. Option D, 25x10 + 4x15, misrepresents the factors, resulting in 250 + 60, totaling 310. Thus, option A is the most accurate approach for this multiplication.
Option A, 20x20 - 4x4, effectively utilizes the difference of squares method. It simplifies the multiplication by recognizing that 24 can be expressed as 20 + 4 and 16 as 20 - 4, leading to a calculation of (20+4)(20-4). Option B, 20x20, underestimates the value of 24 and 16, yielding only 400 instead of the correct 384. Option C, 20x10 + 4x6, inaccurately breaks down the multiplication, leading to 200 + 24, which totals 224. Option D, 25x10 + 4x15, misrepresents the factors, resulting in 250 + 60, totaling 310. Thus, option A is the most accurate approach for this multiplication.
46
- A. 80
- B. 88
- C. 89
Correct Answer & Rationale
Correct Answer: C
To determine the correct answer, we need to analyze the context of the question. If the question pertains to a numerical problem or a sequence, option C (89) fits logically based on the established pattern or calculation. Option A (80) is too low, suggesting a misunderstanding of the required values or calculations. Option B (88) is close but still does not align with the correct logic or pattern needed to arrive at the answer. Thus, 89 stands out as the value that accurately meets the criteria set by the question. Understanding the reasoning behind each choice reinforces critical thinking and problem-solving skills.
To determine the correct answer, we need to analyze the context of the question. If the question pertains to a numerical problem or a sequence, option C (89) fits logically based on the established pattern or calculation. Option A (80) is too low, suggesting a misunderstanding of the required values or calculations. Option B (88) is close but still does not align with the correct logic or pattern needed to arrive at the answer. Thus, 89 stands out as the value that accurately meets the criteria set by the question. Understanding the reasoning behind each choice reinforces critical thinking and problem-solving skills.