tsia2 math practice test

A placement test used in Texas to assess a student's readiness for college-level coursework in math, reading, and writing.

Choose the best answer. If necessary, use the paper you were given.
Which of the following is NOT a factor of x^4 +x^3?
  • A. X
  • B. X + 1
  • C. X^3
  • D. X^4
Correct Answer & Rationale
Correct Answer: D

To determine which option is not a factor of \(x^4 + x^3\), we can factor the expression itself. Factoring out the greatest common factor, we have \(x^3(x + 1)\). - **Option A: X** is a factor since \(x\) is part of \(x^3\). - **Option B: X + 1** is a factor as it is the remaining term after factoring \(x^3\). - **Option C: X^3** is clearly a factor since it is part of the factored expression. **Option D: X^4** is not a factor because \(x^4\) cannot divide \(x^4 + x^3\) without leaving a remainder. Thus, it does not fit into the factorization.

Other Related Questions

Which equation is a correct way to calculate x?
  • A. sin x=5,000 /7,000
  • B. sin x= 7,000 /5,000
  • C. tan x= 5,000/7,000
  • D. tan x=7,000/5,000
Correct Answer & Rationale
Correct Answer: C

To solve for \( x \), the correct relationship involves the tangent function, as \( \tan \) is defined as the ratio of the opposite side to the adjacent side in a right triangle. Option C, \( \tan x = \frac{5,000}{7,000} \), accurately represents this ratio. Option A misapplies the sine function, which should represent the ratio of the opposite side to the hypotenuse, not the adjacent side. Similarly, option B incorrectly uses sine but with the sides reversed, leading to an inaccurate representation. Option D misuses tangent, suggesting the opposite and adjacent sides are swapped, which does not align with the definition of tangent. Thus, only option C correctly applies the tangent function to find \( x \).
The system of equations above has how many solutions? x+4y=3, 2x+8y=4
  • A. None
  • B. One
  • C. Two
  • D. Infinitely many
Correct Answer & Rationale
Correct Answer: A

To determine the number of solutions for the system of equations, we first analyze the equations: \(x + 4y = 3\) and \(2x + 8y = 4\). The second equation can be simplified by dividing all terms by 2, resulting in \(x + 4y = 2\). Now, we have two equations: \(x + 4y = 3\) and \(x + 4y = 2\). Since both equations represent parallel lines (same slope, different y-intercepts), they will never intersect, indicating there are no solutions. Option B suggests one solution, which is incorrect as parallel lines do not meet. Option C suggests two solutions, which is also incorrect for the same reason. Option D proposes infinitely many solutions, which applies only to identical lines, not parallel ones. Thus, the system has no solutions.
If (2w + 7)(3w - 1) = 0 which of the following is a possible value of w?
  • A. -3
  • B. -0.28571
  • C. 01-Mar
  • D. 07-Feb
Correct Answer & Rationale
Correct Answer: D

To solve the equation (2w + 7)(3w - 1) = 0, we set each factor to zero. 1. For 2w + 7 = 0, solving gives w = -3. This corresponds to option A, which is a valid solution. 2. For 3w - 1 = 0, solving gives w = 1/3, approximately 0.333. Option B, -0.28571, does not match this value. 3. Option C, 01-Mar, is not a numerical value but a date format, making it irrelevant. 4. Option D, 07-Feb, while also a date format, can be interpreted as a fraction (7/2), which equals 3.5, not a solution to the equation. Thus, option A is a valid solution, while options B, C, and D do not provide valid values for w.
A bowl contains 6 green grapes, 10 red grapes, and 8 black grapes.Which of the following is the correct calculation for the probability of choosing a red grape and then without putting the red grape back into the bowl, choosing a green grape?
  • A. 10/24+6/24
  • B. 10/24+6/23
  • C. 10/24*6/24
  • D. 10/24*6/23
Correct Answer & Rationale
Correct Answer: D

To determine the probability of selecting a red grape followed by a green grape without replacement, the first step involves calculating the probability of the first event (selecting a red grape). There are 10 red grapes out of a total of 24 grapes, giving a probability of 10/24. After choosing a red grape, there are now 23 grapes left in the bowl, including 6 green grapes. Thus, the probability of then selecting a green grape is 6/23. Option A incorrectly adds the probabilities, which is not appropriate for sequential events. Option B uses the correct second probability but fails to multiply the probabilities of the two events. Option C mistakenly adds both probabilities instead of multiplying them. Only option D correctly multiplies the probabilities of the two dependent events.