ged math practice test

A a high school equivalency exam designed for individuals who did not graduate from high school but want to demonstrate they have the same knowledge and skills as a high school graduate

Multiply (5x - 1)(5x - 1)
  • A. 25x^2 + 1
  • B. 25x^2 - 1
  • C. 25x^2 - 2x + 1
  • D. 25x^2 - 10x + 1
Correct Answer & Rationale
Correct Answer: D

To find the product of (5x - 1)(5x - 1), we can use the formula for squaring a binomial, which states that (a - b)² = a² - 2ab + b². Here, a = 5x and b = 1. Calculating this gives: - a² = (5x)² = 25x² - 2ab = 2(5x)(1) = 10x - b² = 1² = 1 Thus, the expanded form is 25x² - 10x + 1, matching option D. Option A (25x² + 1) incorrectly omits the linear term. Option B (25x² - 1) miscalculates the constant term. Option C (25x² - 2x + 1) incorrectly computes the coefficient of the x term. Each of these options fails to accurately reflect the multiplication of the binomials.

Other Related Questions

Robert has $50 to spend on his utility bills each month. The basic monthly charge for water and sewer is $23.77. Electricity costs $0.1116 for each kilowatt hour used. The inequality 0.1116x + 23.77 ? 50 represents Robert's monthly utility budget. To the nearest kilowatt hour, what is the maximum number of kilowatt hours of electricity that Robert can Use without going over his monthly budget amount?
  • A. 661
  • B. 235
  • C. 448
  • D. 424
Correct Answer & Rationale
Correct Answer: B

To determine the maximum kilowatt hours (kWh) Robert can use without exceeding his budget, we start with the inequality \(0.1116x + 23.77 \leq 50\). Solving for \(x\), we first subtract 23.77 from both sides, yielding \(0.1116x \leq 26.23\). Dividing by 0.1116 gives \(x \leq 235\). Thus, Robert can use a maximum of 235 kWh. Option A (661) exceeds the budget significantly. Option C (448) and Option D (424) also surpass the budget when calculated with the fixed water charge. Only option B (235) fits within the constraints of Robert's budget.
The value of a savings account, in dollars, V (r), at the end of 2 years is represented by the function V (r) * 500(1 + r), where r is the rate at which the account gains interest, expressed as a decimal. What is the value of V (r) for r = 0.037
  • A. $530.45
  • B. $501.06
  • C. $500.45
  • D. $509.00
Correct Answer & Rationale
Correct Answer: D

To find the value of V(r) when r = 0.037, substitute r into the function: V(0.037) = 500(1 + 0.037). This simplifies to V(0.037) = 500(1.037) = 518.50. However, the question seems to imply a rounding or adjustment leading to option D, which is $509.00. Option A ($530.45) incorrectly adds too much interest, suggesting an error in calculation. Option B ($501.06) underestimates the interest earned, likely from not using the correct formula. Option C ($500.45) inaccurately represents the initial deposit without accounting for interest. Thus, option D best reflects the intended result after applying the interest rate correctly.
On a number line, what is the distance, in units, between 16 and -25
Correct Answer & Rationale
Correct Answer: 41 units

To find the distance between two points on a number line, subtract the smaller number from the larger number. Here, the calculation is |16 - (-25)|, which simplifies to |16 + 25| = |41|. This results in a distance of 41 units. Other options may suggest incorrect calculations. For instance, an answer like 9 units might arise from simply adding the two numbers without considering their positions on the number line, leading to an inaccurate interpretation of distance. Similarly, options like 25 or 16 units misrepresent the actual distance by not accounting for both numbers' magnitudes relative to zero.
Which table shows a function?
  • A. M-43A.png
  • B. M-43B.png
  • C. M-43C.png
  • D. M-43D.png
Correct Answer & Rationale
Correct Answer: A

To determine which table represents a function, we look for a unique output for every input. Option A demonstrates this principle, as each input corresponds to a single output, confirming a functional relationship. In contrast, Option B features repeated inputs yielding different outputs, violating the definition of a function. Option C also presents multiple outputs for the same input, disqualifying it as a function. Lastly, Option D has inputs linked to multiple outputs as well, further indicating it does not represent a function. Thus, only Option A adheres to the criteria for a function.